Optimal. Leaf size=144 \[ \frac{x \left (4 a^2 b^2+3 a^4+8 b^4\right )}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \sin (x) \cos (x)}{8 a^3}+\frac{2 b^5 \tanh ^{-1}\left (\frac{a+b \tan \left (\frac{x}{2}\right )}{\sqrt{a^2-b^2}}\right )}{a^5 \sqrt{a^2-b^2}}+\frac{b \sin ^2(x) \cos (x)}{3 a^2}-\frac{\sin ^3(x) \cos (x)}{4 a} \]
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Rubi [A] time = 0.588463, antiderivative size = 144, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.538, Rules used = {3853, 4104, 3919, 3831, 2660, 618, 206} \[ \frac{x \left (4 a^2 b^2+3 a^4+8 b^4\right )}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \sin (x) \cos (x)}{8 a^3}+\frac{2 b^5 \tanh ^{-1}\left (\frac{a+b \tan \left (\frac{x}{2}\right )}{\sqrt{a^2-b^2}}\right )}{a^5 \sqrt{a^2-b^2}}+\frac{b \sin ^2(x) \cos (x)}{3 a^2}-\frac{\sin ^3(x) \cos (x)}{4 a} \]
Antiderivative was successfully verified.
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Rule 3853
Rule 4104
Rule 3919
Rule 3831
Rule 2660
Rule 618
Rule 206
Rubi steps
\begin{align*} \int \frac{\sin ^4(x)}{a+b \csc (x)} \, dx &=-\frac{\cos (x) \sin ^3(x)}{4 a}+\frac{\int \frac{\left (-4 b+3 a \csc (x)+3 b \csc ^2(x)\right ) \sin ^3(x)}{a+b \csc (x)} \, dx}{4 a}\\ &=\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}-\frac{\int \frac{\left (-3 \left (3 a^2+4 b^2\right )-a b \csc (x)+8 b^2 \csc ^2(x)\right ) \sin ^2(x)}{a+b \csc (x)} \, dx}{12 a^2}\\ &=-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}+\frac{\int \frac{\left (-8 b \left (2 a^2+3 b^2\right )+a \left (9 a^2-4 b^2\right ) \csc (x)+3 b \left (3 a^2+4 b^2\right ) \csc ^2(x)\right ) \sin (x)}{a+b \csc (x)} \, dx}{24 a^3}\\ &=\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}-\frac{\int \frac{-3 \left (3 a^4+4 a^2 b^2+8 b^4\right )-3 a b \left (3 a^2+4 b^2\right ) \csc (x)}{a+b \csc (x)} \, dx}{24 a^4}\\ &=\frac{\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}-\frac{b^5 \int \frac{\csc (x)}{a+b \csc (x)} \, dx}{a^5}\\ &=\frac{\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}-\frac{b^4 \int \frac{1}{1+\frac{a \sin (x)}{b}} \, dx}{a^5}\\ &=\frac{\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}-\frac{\left (2 b^4\right ) \operatorname{Subst}\left (\int \frac{1}{1+\frac{2 a x}{b}+x^2} \, dx,x,\tan \left (\frac{x}{2}\right )\right )}{a^5}\\ &=\frac{\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}+\frac{\left (4 b^4\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (1-\frac{a^2}{b^2}\right )-x^2} \, dx,x,\frac{2 a}{b}+2 \tan \left (\frac{x}{2}\right )\right )}{a^5}\\ &=\frac{\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}+\frac{2 b^5 \tanh ^{-1}\left (\frac{b \left (\frac{a}{b}+\tan \left (\frac{x}{2}\right )\right )}{\sqrt{a^2-b^2}}\right )}{a^5 \sqrt{a^2-b^2}}+\frac{b \left (2 a^2+3 b^2\right ) \cos (x)}{3 a^4}-\frac{\left (3 a^2+4 b^2\right ) \cos (x) \sin (x)}{8 a^3}+\frac{b \cos (x) \sin ^2(x)}{3 a^2}-\frac{\cos (x) \sin ^3(x)}{4 a}\\ \end{align*}
Mathematica [A] time = 0.315207, size = 129, normalized size = 0.9 \[ \frac{48 a^2 b^2 x-24 a^2 b^2 \sin (2 x)+24 a b \left (3 a^2+4 b^2\right ) \cos (x)-\frac{192 b^5 \tan ^{-1}\left (\frac{a+b \tan \left (\frac{x}{2}\right )}{\sqrt{b^2-a^2}}\right )}{\sqrt{b^2-a^2}}-8 a^3 b \cos (3 x)+36 a^4 x-24 a^4 \sin (2 x)+3 a^4 \sin (4 x)+96 b^4 x}{96 a^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.079, size = 405, normalized size = 2.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.581091, size = 909, normalized size = 6.31 \begin{align*} \left [\frac{12 \, \sqrt{a^{2} - b^{2}} b^{5} \log \left (\frac{{\left (a^{2} - 2 \, b^{2}\right )} \cos \left (x\right )^{2} + 2 \, a b \sin \left (x\right ) + a^{2} + b^{2} + 2 \,{\left (b \cos \left (x\right ) \sin \left (x\right ) + a \cos \left (x\right )\right )} \sqrt{a^{2} - b^{2}}}{a^{2} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2}}\right ) - 8 \,{\left (a^{5} b - a^{3} b^{3}\right )} \cos \left (x\right )^{3} + 3 \,{\left (3 \, a^{6} + a^{4} b^{2} + 4 \, a^{2} b^{4} - 8 \, b^{6}\right )} x + 24 \,{\left (a^{5} b - a b^{5}\right )} \cos \left (x\right ) + 3 \,{\left (2 \,{\left (a^{6} - a^{4} b^{2}\right )} \cos \left (x\right )^{3} -{\left (5 \, a^{6} - a^{4} b^{2} - 4 \, a^{2} b^{4}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{24 \,{\left (a^{7} - a^{5} b^{2}\right )}}, \frac{24 \, \sqrt{-a^{2} + b^{2}} b^{5} \arctan \left (-\frac{\sqrt{-a^{2} + b^{2}}{\left (b \sin \left (x\right ) + a\right )}}{{\left (a^{2} - b^{2}\right )} \cos \left (x\right )}\right ) - 8 \,{\left (a^{5} b - a^{3} b^{3}\right )} \cos \left (x\right )^{3} + 3 \,{\left (3 \, a^{6} + a^{4} b^{2} + 4 \, a^{2} b^{4} - 8 \, b^{6}\right )} x + 24 \,{\left (a^{5} b - a b^{5}\right )} \cos \left (x\right ) + 3 \,{\left (2 \,{\left (a^{6} - a^{4} b^{2}\right )} \cos \left (x\right )^{3} -{\left (5 \, a^{6} - a^{4} b^{2} - 4 \, a^{2} b^{4}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{24 \,{\left (a^{7} - a^{5} b^{2}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin ^{4}{\left (x \right )}}{a + b \csc{\left (x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.38791, size = 340, normalized size = 2.36 \begin{align*} -\frac{2 \,{\left (\pi \left \lfloor \frac{x}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (b\right ) + \arctan \left (\frac{b \tan \left (\frac{1}{2} \, x\right ) + a}{\sqrt{-a^{2} + b^{2}}}\right )\right )} b^{5}}{\sqrt{-a^{2} + b^{2}} a^{5}} + \frac{{\left (3 \, a^{4} + 4 \, a^{2} b^{2} + 8 \, b^{4}\right )} x}{8 \, a^{5}} + \frac{9 \, a^{3} \tan \left (\frac{1}{2} \, x\right )^{7} + 12 \, a b^{2} \tan \left (\frac{1}{2} \, x\right )^{7} + 24 \, b^{3} \tan \left (\frac{1}{2} \, x\right )^{6} + 33 \, a^{3} \tan \left (\frac{1}{2} \, x\right )^{5} + 12 \, a b^{2} \tan \left (\frac{1}{2} \, x\right )^{5} + 48 \, a^{2} b \tan \left (\frac{1}{2} \, x\right )^{4} + 72 \, b^{3} \tan \left (\frac{1}{2} \, x\right )^{4} - 33 \, a^{3} \tan \left (\frac{1}{2} \, x\right )^{3} - 12 \, a b^{2} \tan \left (\frac{1}{2} \, x\right )^{3} + 64 \, a^{2} b \tan \left (\frac{1}{2} \, x\right )^{2} + 72 \, b^{3} \tan \left (\frac{1}{2} \, x\right )^{2} - 9 \, a^{3} \tan \left (\frac{1}{2} \, x\right ) - 12 \, a b^{2} \tan \left (\frac{1}{2} \, x\right ) + 16 \, a^{2} b + 24 \, b^{3}}{12 \,{\left (\tan \left (\frac{1}{2} \, x\right )^{2} + 1\right )}^{4} a^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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